The mass of silver deposited on the iron ring is **12.0 g/hour**. We need to find the time needed for the iron ring to increase in mass by **3.4 g**.
Let’s use the formula:
`mass = rate × time`
where `mass` is the mass of silver deposited on the iron ring, `rate` is the rate of deposition of silver on the iron ring and `time` is the time taken for the iron ring to increase in mass by 3.4 g.
Rearranging this formula to solve for `time`, we get:
`time = mass / rate`
Substituting the given values, we get:
`time = 3.4 g / 12.0 g/hour`
Converting hours to minutes, we get:
`time = 3.4 g / 12.0 g/hour × 60 minutes/hour = 17 minutes`
Therefore, it would take **17 minutes** for the iron ring to increase in mass by **3.4 g** if silver is deposited on the iron ring at a rate of **12.0 g per hour**.